![Range of the function f(x)=sqrt(cos^(- 1)(sqrt(log4x))-pi/2)+sin^(- 1)((1+x^ 2)/(4x)) is equal to (A) (0,pi/2+sqrt(pi/2)] (B) [pi/2,pi/2+sqrt(pi/2)] (C) [pi/6,pi/4) (D) {pi/6} Range of the function f(x)=sqrt(cos^(- 1)(sqrt(log4x))-pi/2)+sin^(- 1)((1+x^ 2)/(4x)) is equal to (A) (0,pi/2+sqrt(pi/2)] (B) [pi/2,pi/2+sqrt(pi/2)] (C) [pi/6,pi/4) (D) {pi/6}](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/642539147_web.png)
Range of the function f(x)=sqrt(cos^(- 1)(sqrt(log4x))-pi/2)+sin^(- 1)((1+x^ 2)/(4x)) is equal to (A) (0,pi/2+sqrt(pi/2)] (B) [pi/2,pi/2+sqrt(pi/2)] (C) [pi/6,pi/4) (D) {pi/6}
![lim(xrarr1^(-)) (sqrtpi-sqrt(2sin^-1x))/sqrt(1-x)= (A) sqrt(2/pi) (B) sqrt( pi/2) (C) 1/pi (D) sqrt(1/pi) lim(xrarr1^(-)) (sqrtpi-sqrt(2sin^-1x))/sqrt(1-x)= (A) sqrt(2/pi) (B) sqrt( pi/2) (C) 1/pi (D) sqrt(1/pi)](https://d10lpgp6xz60nq.cloudfront.net/ss/web/1161095.jpg)
lim(xrarr1^(-)) (sqrtpi-sqrt(2sin^-1x))/sqrt(1-x)= (A) sqrt(2/pi) (B) sqrt( pi/2) (C) 1/pi (D) sqrt(1/pi)
![SOLVED: Which one of the following best describe the SD of a 0 - 1 (count) box? Hint: 1) pi = average of count box: 2) sqrt Square Root: 3) Y^2 = SOLVED: Which one of the following best describe the SD of a 0 - 1 (count) box? Hint: 1) pi = average of count box: 2) sqrt Square Root: 3) Y^2 =](https://cdn.numerade.com/ask_images/de9a1646a98646a28cc75ef983c533f2.jpg)
SOLVED: Which one of the following best describe the SD of a 0 - 1 (count) box? Hint: 1) pi = average of count box: 2) sqrt Square Root: 3) Y^2 =
![int_(0)^((pi)/(2))(dx)/(a+bcosx)(agtb)=(2)/(sqrt(a^(2)-b^(2)))tan^(-1)sqrt((a-b)/(a+b)) | 12 | ... - YouTube int_(0)^((pi)/(2))(dx)/(a+bcosx)(agtb)=(2)/(sqrt(a^(2)-b^(2)))tan^(-1)sqrt((a-b)/(a+b)) | 12 | ... - YouTube](https://i.ytimg.com/vi/CA1NPDQ_pUo/maxresdefault.jpg)
int_(0)^((pi)/(2))(dx)/(a+bcosx)(agtb)=(2)/(sqrt(a^(2)-b^(2)))tan^(-1)sqrt((a-b)/(a+b)) | 12 | ... - YouTube
How to calculate the limit of [math]\frac{2-\sqrt{3} \cos x-\sin x}{6x-\pi}^{²}[/math] when [math]x\rightarrow\frac{\pi}{6}[/math] - Quora
![geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange](https://i.stack.imgur.com/pFBV3.png)
geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange
![The volume of the solid generated by revolving the curve y = square root sin 2 x, 0 less than or equal to x less than or equal to pi / 2, The volume of the solid generated by revolving the curve y = square root sin 2 x, 0 less than or equal to x less than or equal to pi / 2,](https://homework.study.com/cimages/multimages/16/disk_meth5645421034356429220.png)
The volume of the solid generated by revolving the curve y = square root sin 2 x, 0 less than or equal to x less than or equal to pi / 2,
![geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange](https://i.stack.imgur.com/yPEWc.jpg)